In case of a bipolar transistor,$\beta = 45$. The potential drop across the collector resistance of $1 \ k\Omega$ is $5 \ V$. The base current is approximately: (in $\mu A$)

In the circuit shown,the transistor used has a current gain $\beta = 100$. What should be the base resistor $R_B$ so that $V_{CE} = 5\,V$ and $V_{BE} = 0\,V$?

$NPN$ transistors are preferred to $PNP$ transistors because they have

In the study of a transistor as an amplifier,if $\alpha = \frac{I_{C}}{I_{E}}$ and $\beta = \frac{I_{C}}{I_{B}}$,where $I_{C}$,$I_{B}$,and $I_{E}$ are the collector,base,and emitter currents respectively,then:

For a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2 \, k\Omega$ is $4 \, V$. If the current amplification factor $(\beta)$ of the transistor is $100$ and the base resistance is $1 \, k\Omega$,then the input signal voltage is ....... $mV$.

In the following transistor circuit,$R_i$ is the input resistance and $R_0$ is the output resistance. The approximate voltage gain for the circuit is: