$NPN$ transistors are preferred to $PNP$ transistors because they have

  • A
    Low cost
  • B
    Low dissipation energy
  • C
    Capability of handling large power
  • D
    Electrons having high mobility than holes

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In the following common emitter circuit, if $\beta=100$, $V_{CE}=7 \, V$, $V_{BE}$ is negligible, and $R_C=2 \, k\Omega$, then $I_B=$ (in $\, mA$)?

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