(D) Given: Collector resistance $R_C = 2 \, k\Omega = 2000 \, \Omega$,Output voltage $V_0 = 4 \, V$,Current amplification factor $\beta = 100$,Base re

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) Given: Collector resistance $R_C = 2 \, k\Omega = 2000 \, \Omega$,Output voltage $V_0 = 4 \, V$,Current amplification factor $\beta = 100$,Base resistance $R_B = 1 \, k\Omega = 1000 \, \Omega$.The voltage gain $A_v$ of a $CE$ amplifier is given by the formula: $A_v = \beta \times \frac{R_C}{R_B}$.Substituting the values: $A_v = 100 \times \frac{2000}{1000} = 200$.We know that voltage gain $A_v = \frac{V_0}{V_i}$,where $V_i$ is the input signal voltage.Therefore,$V_i = \frac{V_0}{A_v} = \frac{4 \, V}{200} = 0.02 \, V$.Converting to millivolts $(mV)$: $V_i = 0.02 \times 1000 \, mV = 20 \, mV$.

Class 12 Physics Semiconductor Electronics Junction Transistor

Medium

For a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2 \, k\Omega$ is $4 \, V$. If the current amplification factor $(\beta)$ of the transistor is $100$ and the base resistance is $1 \, k\Omega$,then the input signal voltage is ....... $mV$.

NEET 2016 All NEET

A
$30$
B
$15$
C
$10$
D
$20$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Semiconductor Electronics

Subtopic

Junction Transistor

Previous Year

NEET 2016 Paper All NEET years →

In the common emitter configuration of a transistor,the current gain is more than $1$. Given that $I_{b}$,$I_{e}$,and $I_{c}$ are the base,emitter,and collector currents respectively,which of the following relations is correct?

EasyMHT CET 2020

View Solution

The current amplification factor of a transistor is $50$. In a $CE$ amplifier circuit, the collector resistance is $5 \, k\Omega$ and the input resistance is $1 \, k\Omega$. If the input voltage is $0.01 \, V$, the output voltage is ........ $V$.

Medium

View Solution

In an amplifier circuit,the value of the load resistance $R_L$ is $2 \text{ k}\Omega$. $A$ change of $10 \text{ }\mu\text{A}$ in the base current of the transistor results in a change of $1 \text{ mA}$ in the collector current. The change in the collector-emitter voltage $(V_{CE})$ is ....... $V$.

Easy

View Solution

For a common emitter transistor amplifier, the current gain is $\beta = 100$. Given the input voltage $V_{in} = 1 \text{ mV}$, input resistance $R_{in} = 1 \text{ k}\Omega$, and load resistance $R_L = 10 \text{ k}\Omega$, calculate the output voltage $V_{out}$ in $\text{V}$.

Difficult

View Solution

For a transistor amplifier in a common-emitter configuration,given the load resistance $R_L = 1 \ k\Omega$,$h_{fe} = 50$,and $h_{oe} = 25 \ \mu A/V$,calculate the current gain $(A_i)$.

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

For a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2 \, k\Omega$ is $4 \, V$. If the current amplification factor $(\beta)$ of the transistor is $100$ and the base resistance is $1 \, k\Omega$,then the input signal voltage is ....... $mV$.

Similar Questions

In the common emitter configuration of a transistor,the current gain is more than $1$. Given that $I_{b}$,$I_{e}$,and $I_{c}$ are the base,emitter,and collector currents respectively,which of the following relations is correct?

The current amplification factor of a transistor is $50$. In a $CE$ amplifier circuit, the collector resistance is $5 \, k\Omega$ and the input resistance is $1 \, k\Omega$. If the input voltage is $0.01 \, V$, the output voltage is ........ $V$.

In an amplifier circuit,the value of the load resistance $R_L$ is $2 \text{ k}\Omega$. $A$ change of $10 \text{ }\mu\text{A}$ in the base current of the transistor results in a change of $1 \text{ mA}$ in the collector current. The change in the collector-emitter voltage $(V_{CE})$ is ....... $V$.

For a common emitter transistor amplifier, the current gain is $\beta = 100$. Given the input voltage $V_{in} = 1 \text{ mV}$, input resistance $R_{in} = 1 \text{ k}\Omega$, and load resistance $R_L = 10 \text{ k}\Omega$, calculate the output voltage $V_{out}$ in $\text{V}$.

For a transistor amplifier in a common-emitter configuration,given the load resistance $R_L = 1 \ k\Omega$,$h_{fe} = 50$,and $h_{oe} = 25 \ \mu A/V$,calculate the current gain $(A_i)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module