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(C) From the collector circuit,applying Kirchhoff's voltage law:$V_{CC} = I_C R_L + V_{CE}$Given $V_{CC} = 10\,V$,$R_L = 1\,k\Omega = 1000\,\Omega$,an

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$200 	imes 10^3\,\Omega$

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(C) From the collector circuit,applying Kirchhoff's voltage law:$V_{CC} = I_C R_L + V_{CE}$Given $V_{CC} = 10\,V$,$R_L = 1\,k\Omega = 1000\,\Omega$,and $V_{CE} = 5\,V$.$10 = I_C 	imes 1000 + 5$$I_C 	imes 1000 = 5$$I_C = 5 	imes 10^{-3}\,A = 5\,mA$Now,using the current gain relation $I_C = \beta I_B$:$I_B = \frac{I_C}{\beta} = \frac{5 	imes 10^{-3}}{100} = 5 	imes 10^{-5}\,A$From the base circuit,applying Kirchhoff's voltage law:$V_{CC} = I_B R_B + V_{BE}$Given $V_{BE} = 0\,V$:$10 = (5 	imes 10^{-5}) 	imes R_B + 0$$R_B = \frac{10}{5 	imes 10^{-5}} = 2 	imes 10^5\,\Omega = 200 	imes 10^3\,\Omega$Thus,the correct option is $C$.

In the circuit shown,the transistor used has a current gain $\beta = 100$. What should be the base resistor $R_B$ so that $V_{CE} = 5\,V$ and $V_{BE} = 0\,V$?

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