In an E. coli strain,the i gene gets mutated | vedclass

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(B) In the $lac$ operon,the $i$ gene codes for a repressor protein. Normally,the repressor protein binds to the operator region and prevents $RNA$ pol

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$z, y, a$ genes will not be translated

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(B) In the $lac$ operon,the $i$ gene codes for a repressor protein. Normally,the repressor protein binds to the operator region and prevents $RNA$ polymerase from transcribing the structural genes $(z, y, a)$. When lactose (the inducer) is present,it binds to the repressor protein,causing a conformational change that prevents the repressor from binding to the operator. In this specific case,the mutated $i$ gene produces a repressor that cannot bind the inducer (lactose). Therefore,the repressor remains bound to the operator regardless of the presence of lactose. As a result,the $RNA$ polymerase is blocked from transcribing the structural genes $(z, y, a)$. Since transcription does not occur,the genes will not be translated into proteins.

List-$I$	List-$II$
$a$. In lac operon $i$ gene codes for	$i$. Transacetylase
$b$. In lac operon $z$ gene codes for	$ii$. Permease
$c$. In lac operon $y$ gene codes for	$iii$. $\beta$-galactosidase
$d$. In lac operon $a$ gene codes for	$iv$. Repressor

In an $E. coli$ strain,the $i$ gene gets mutated such that its product cannot bind the inducer molecule. If the growth medium is provided with lactose,what will be the outcome?

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