In a hostel,60 % of the students read Hindi n | vedclass

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Question

(B) Let $H$ be the event that a student reads Hindi newspaper and $E$ be the event that a student reads English newspaper.Given:$P(H) = 60\% = 0.6 = 3

Vedclass · Accepted Answer

$1/2$

Vedclass · Answer

(B) Let $H$ be the event that a student reads Hindi newspaper and $E$ be the event that a student reads English newspaper.Given:$P(H) = 60\% = 0.6 = 3/5$$P(E) = 40\% = 0.4 = 2/5$$P(H \cap E) = 20\% = 0.2 = 1/5$We need to find the conditional probability $P(H | E)$,which is the probability that a student reads Hindi newspaper given that she reads English newspaper.Using the formula for conditional probability:$P(H | E) = \frac{P(H \cap E)}{P(E)}$Substituting the values:$P(H | E) = \frac{1/5}{2/5} = \frac{1}{2}$

In a hostel,$60 \%$ of the students read Hindi newspaper,$40 \%$ read English newspaper and $20 \%$ read both Hindi and English newspapers. $A$ student is selected at random. If she reads English newspaper,find the probability that she reads Hindi newspaper.

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