A bag contains 9 discs of which 4 are red,3 a | vedclass

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(C) Total number of discs $= 4 + 3 + 2 = 9$.Total number of possible outcomes $= 9$.Let $R$ be the event of drawing a red disc and $B$ be the event of

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$\frac{7}{9}$

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(C) Total number of discs $= 4 + 3 + 2 = 9$.Total number of possible outcomes $= 9$.Let $R$ be the event of drawing a red disc and $B$ be the event of drawing a blue disc.Number of red discs $= 4$,so $P(R) = \frac{4}{9}$.Number of blue discs $= 3$,so $P(B) = \frac{3}{9}$.Since the events are mutually exclusive,the probability of drawing either red or blue is $P(R \cup B) = P(R) + P(B)$.$P(R \cup B) = \frac{4}{9} + \frac{3}{9} = \frac{7}{9}$.

$A$ bag contains $9$ discs of which $4$ are red,$3$ are blue,and $2$ are yellow. The discs are similar in shape and size. $A$ disc is drawn at random from the bag. Calculate the probability that it will be either red or blue.

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