Imagine a new planet having the same density as that of earth but it is $3$ times bigger than the earth in size. If the acceleration due to gravity on the surface of earth is $g$ and that on the surface of the new planet is $g^{\prime}$, then

A satellite revolves in the geostationary orbit but in a direction east to west. The time interval between its successive passing about a point on the equator is ........ $hrs$

$Assertion$ : An astronaut experience weightlessness in a space satellite.

$Reason$ : When a body falls freely it does not experience gravity

If the value of $‘g’$ acceleration due to gravity, at earth surface is $10\,m/{s^2}$, its value in $m/{s^2}$ at the centre of the earth, which is assumed to be a sphere of radius ‘R’ metre and uniform mass density is

A body weight $W$, is projected vertically upwards from earth's surface to reach a height above the earth which is equal to nine times the radius of earth. The weight of the body at that height will be

A $90 \mathrm{~kg}$ body placed at $2 \mathrm{R}$ distance from surface of earth experiences gravitational pull of : ( $\mathrm{R}=$ Radius of earth, $\mathrm{g}=10 \mathrm{~ms}^{-2}$ )