If the value of $‘g’$ acceleration due to gravity, at earth surface is $10\,m/{s^2}$, its value in $m/{s^2}$ at the centre of the earth, which is assumed to be a sphere of radius ‘R’ metre and uniform mass density is

A uniform spherical planet (Radius $R$) has acceleration due to gravity at its surface $g.$ Points $P$ and $Q$ located inside and outside the planet have acceleration due to gravity $\frac{g}{4} .$ Maximum possible separation between $P$ and $Q$ is

An iron ball and a wooden ball of the same radius are released from a height $‘h’$ in vacuum. The time taken by both of them to reach the ground is

The weight of a body at the centre of the earth is

Assuming earth to be a sphere of a uniform density, what is the value of gravitational acceleration in a mine $100\, km$ below the earth’s surface ........ $m/{s^2}$. (Given $R = 6400 \,km$)

A body weighs $144 \,N$ at the surface of earth. When it is taken to a height of $h=3 \,R$, where $R$ is radius of earth, it would weigh .......... $N$