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(C) The heat generated $H$ is given by the formula $H = \frac{V^2 t}{R}$.Since the voltage $V$ and time $t$ are constant,we have $H \propto \frac{1}{R

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$2:9$

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(C) The heat generated $H$ is given by the formula $H = \frac{V^2 t}{R}$.Since the voltage $V$ and time $t$ are constant,we have $H \propto \frac{1}{R}$.For series connection,the equivalent resistance is $R_S = R + 2R = 3R$.For parallel connection,the equivalent resistance is $R_P = \frac{R 	imes 2R}{R + 2R} = \frac{2R^2}{3R} = \frac{2}{3}R$.The ratio of heat generated in series to parallel is $\frac{H_S}{H_P} = \frac{R_P}{R_S}$.Substituting the values,we get $\frac{H_S}{H_P} = \frac{(2/3)R}{3R} = \frac{2}{9}$.

If two wires having resistance $R$ and $2R$ are joined in series and then in parallel,what is the ratio of heat generated in these two situations,assuming the same voltage is applied?

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