The two bulbs as in the above question are connected in series to a $200\, volt$ line. Then
The potential drop across the two bulbs is the same
The potential drop across the $40\, watt$ bulb is greater than the potential drop across the $100\, watt$ bulb
The potential drop across the $100\, watt$ bulb is greater than the potential drop across the $40\, watt$ bulb
The potential drop across both the bulb is $200\, volt$
The capacitor $C$ is initially without charge.$X$ is now j oined to $Y$ for a long time, during which $H_1$ heat is produced in the resistance $R$. $X-Y$ connection is removed and $X$ is now joined to $Z$ for a long time, during which heat $H_2$ is produced in $R$.
Figure shows three similar lamps $L_1, L_2$ and $L_3$ connected across a power supply. If the lamp $L_3$ fuses, how will the light emitted by $L_1$ and $L_2$ change ?
An electric fan and a heater are marked as $100\, watt$, $220\, volt$ and $1000\, watt$, $220\, volt$ respectively. The resistance of the heater is
The supply voltage to room is $120\ V$. The resistance of the lead wires is $6\,\Omega$ . A $60\ W$ bulb is already switched on. What is the decrease of voltage across the bulb, when a $240\ W$ heater is switched on in parallel to the bulb? ............. $V$
Water fall from a $40\,m$ high dam at the rate of $9 \times 10^{4}\,kg$ per $hour$. Fifty percentage of gravitational potential energy can be converted into electrical energy. Using this hydroelectric energy number of $100\,W$ lamps, that can be lit, is
(Take $\left.g=10\,ms ^{-2}\right)$