In the following circuit, 5 Omega resistor de | vedclass

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Question

(b) $\frac{{{i_1}}}{{{i_2}}} = \frac{{15}}{5} = \frac{3}{1}$&hellip; $(i)$
Also $\frac{H}{t} = {i^2}R \Rightarrow 45 = {({i_1})^2} 	imes 5$
$ \Righ

Vedclass · Accepted Answer

$192$

Vedclass · Answer

(b) $\frac{{{i_1}}}{{{i_2}}} = \frac{{15}}{5} = \frac{3}{1}$&hellip; $(i)$
Also $\frac{H}{t} = {i^2}R \Rightarrow 45 = {({i_1})^2} 	imes 5$
$ \Rightarrow $ ${i_1} = 3\,A$ and from equation $(i)$ ${i_2} = 1\,A$
So $i = {i_1} + {i_2} = 4\,A$
Hence power developed in $12\,\Omega $ resistance $P = {i^2}R = {(4)^2} 	imes 12 = 192\,W$

In the following circuit, $5$ $\Omega$ resistor develops $45$ $J/s$ due to current flowing through it. The power developed per second across $12$ $\Omega$ resistor is ............. $W$

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