If the graph of y = ax^3 + bx^2 + cx + d is s | vedclass

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Question

$	herefore a=0$ and $y=b x^{2}+c x+d$ is symmetric

about $x=-\frac{c}{2 b}$

$	herefore \mathrm{x}=\mathrm{k}=-\frac{c}{2 b} \Rightarrow k+\fra

Vedclass · Accepted Answer

$a + \frac{c}{{2b}} + k = 0$

Vedclass · Answer

$	herefore a=0$ and $y=b x^{2}+c x+d$ is symmetric

about $x=-\frac{c}{2 b}$

$	herefore \mathrm{x}=\mathrm{k}=-\frac{c}{2 b} \Rightarrow k+\frac{c}{2 b}=0$

$\Rightarrow a+\frac{c}{2 b}+k=0$

If the graph of $y = ax^3 + bx^2 + cx + d$ is symmetric about the line $x = k$ then

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