Below are four equations in x. Assume that 0 | vedclass

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Question

(b)

Given,$0 < r < 4$

$A=5\left(1+\frac{r}{\pi}\right)^x=9$

$\left(1+\frac{r}{\pi}\right)^x=\frac{9}{5}$

$B=\left(1+\frac{r}{17}\rig

Vedclass · Accepted Answer

$5\left(1+\frac{r}{17}\right)^x=9$

Vedclass · Answer

(b)

Given,$0 < r < 4$

$A=5\left(1+\frac{r}{\pi}ight)^x=9$

$\left(1+\frac{r}{\pi}ight)^x=\frac{9}{5}$

$B=\left(1+\frac{r}{17}ight)^x=\frac{9}{5}$

$C=(1+2 r)^x=\frac{9}{5}$

$D=\left(1+\frac{1}{r}ight)^x=\frac{9}{5}$

All $A, B, C, D$ are in the form of $(a)^x=b$ $x$ is largest when $a$ is smallest.

$	herefore \operatorname{In} A, B, C, D$

$ 0 < r < 4$

$1+\frac{r}{17}$ is smallest

Option $(b)$ is correct.

Below are four equations in $x$. Assume that $0 < r < 4$. Which of the following equations has the largest solution for $x$ ?

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