If the foci of an ellipse are $( \pm \sqrt 5 ,\,0)$ and its eccentricity is $\frac{{\sqrt 5 }}{3}$, then the equation of the ellipse is
If the foci of an ellipse are $( \pm \sqrt 5 ,\,0)$ and its eccentricity is $\frac{{\sqrt 5 }}{3}$, then the equation of the ellipse is
- A
$9{x^2} + 4{y^2} = 36$
- B
$4{x^2} + 9{y^2} = 36$
- C
$36{x^2} + 9{y^2} = 4$
- D
$9{x^2} + 36{y^2} = 4$
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