If the ellipse $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ meets the line $\frac{x}{7}+\frac{y}{2\sqrt{6}}=1$ on the $x$-axis and the line $\frac{x}{7}-\frac{y}{2\sqrt{6}}=1$ on the $y$-axis,then the eccentricity of the ellipse is

  • A
    $\frac{5}{7}$
  • B
    $\frac{2\sqrt{6}}{7}$
  • C
    $\frac{3}{7}$
  • D
    $\frac{2\sqrt{5}}{7}$

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