If the circles $x^{2}+y^{2}+2x+2ky+6=0$ and $x^{2}+y^{2}+2ky+k=0$ intersect orthogonally,then $k$ is

  • A
    $2$ or $-3/2$
  • B
    $-2$ or $-3/2$
  • C
    $2$ or $3/2$
  • D
    $-2$ or $3/2$

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