If the circles (x+1)^2+(y+2)^2=r^2 and x^2+y^ | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

If two circles intersect at two distinct points

$\Rightarrow\left|\mathrm{r}_1-\mathrm{r}_2\right|<\mathrm{C}_1 \mathrm{C}_2<\mathrm{r}_1+\ma

Vedclass · Accepted Answer

$3<$ r $<7$

Vedclass · Answer

If two circles intersect at two distinct points $\Rightarrow\left|\mathrm{r}_1-\mathrm{r}_2 ight|<\mathrm{C}_1 \mathrm{C}_2<\mathrm{r}_1+\mathrm{r}_2$ $ |\mathrm{r}-2|<\sqrt{9+16}<\mathrm{r}+2 $ $ |\mathrm{r}-2|<5 ext { and } \mathrm{r}+2>5$ $ -5<\mathrm{r}-2<5$ $r>3$ $.............(1)$ $-3<\mathrm{r}<7$ $..................(2)$ From $(1)$ and $(2)$ $3<\mathrm{r}<7$

If the circles $(x+1)^2+(y+2)^2=r^2$ and $x^2+y^2-4 x-4 y+4=0$ intersect at exactly two distinct points, then

Similar Questions

$P$ is a point $(a, b)$ in the first quadrant. If the two circles which pass through $P$ and touch both the co-ordinate axes cut at right angles, then :

The circles $x^2 + y^2 + 2x -2y + 1 = 0$ and $x^2 + y^2 -2x -2y + 1 = 0$ touch each other :-

The radical axis of the pair of circle ${x^2} + {y^2} = 144$ and ${x^2} + {y^2} - 15x + 12y = 0$ is

A circle $C_1$ of radius $2$ touches both $x$ -axis and $y$ -axis. Another circle $C_2$ whose radius is greater than $2$ touches circle $C_1$ and both the axes. Then the radius of circle $C_2$ is-

If $d$ is the distance between the centres of two circles, ${r_1},{r_2}$ are their radii and $d = {r_1} + {r_2}$, then