If the atom _{100}F{m^{257}} follows the Bohr | vedclass

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(d) $({r_m}) = \left( {\frac{{{m^2}}}{Z}} ight)\,(0.53{\mathring A}) = (n 	imes 0.53{\mathring A})$
==> $\frac{{{m^2}}}{Z} = n$
$m = 5$ for $_

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$0.25$

Vedclass · Answer

(d) $({r_m}) = \left( {\frac{{{m^2}}}{Z}} ight)\,(0.53{\mathring A}) = (n 	imes 0.53{\mathring A})$
==> $\frac{{{m^2}}}{Z} = n$
$m = 5$ for $_{100}F{m^{257}}$         (the outermost shell)
and $z = 100$ ==> $n = \frac{{{{(5)}^2}}}{{100}} = \frac{1}{4}$

If the atom $_{100}F{m^{257}}$ follows the Bohr model and the radius of $_{100}F{m^{257}}$ is $n$ times the Bohr radius, then find $n$

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