The first line in the Lyman series has wavele | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

For first line in Lyman series $\lambda_{L_{1}}=\frac{4}{3 R}$           ...........$(i)$

For first line in Balmer se

Vedclass · Accepted Answer

$\frac{27}{5}\lambda $

Vedclass · Answer

For first line in Lyman series $\lambda_{L_{1}}=\frac{4}{3 R}$           ...........$(i)$

For first line in Balmer series $\lambda_{B_{1}}=\frac{36}{5 R}$            ............$(ii)$

From equations $(i)$ and $(ii)$

$\frac{\lambda_{\mathrm{B}_{1}}}{\lambda_{\mathrm{L}_{1}}}=\frac{27}{5}$

$ \Rightarrow \lambda_{\mathrm{B}_{1}} \frac{27}{5} \lambda_{\mathrm{L}_{1}} $

$\Rightarrow \lambda_{\mathrm{B}_{1}} \frac{27}{5} \lambda$

List $- I$	List $- II$
$(1)$ Davisson and Genner	$(i)$ Wave nature of electrons
$(2)$ Millikan's oil drop experiment	$(ii)$ Charge of an electron
$(3)$ Rutherford experiment	$(iii)$ Quantisation of energy levels
$(4)$ Franck-Hertz experiment	$(iv)$ Existence of nucleus

The first line in the Lyman series has wavelength $\lambda $. The wavlength of the first line in Balmer series is

Similar Questions

Give a powerful way to determine an upper limit to the size of the electron.

If the force between the electron in the first Bohr orbit and the nucleus (proton) in hydrogen atom is $F$, then the force between them when the electron is in the second orbit is

The wavelengths of ${K_\alpha }$ $X-$ rays of two metals $'A'$ and $'B'$ $\frac{4}{{1875R}}$ and $\frac{1}{{675R}}$ respectively, where $'R'$ is Rydberg's constant. The number of elements lying between $'A'$ and $'B'$ according to their atomic numbers is

An $X-$ ray tube is operated at $50\, kV$. the minimum wavelength produced is.......$\mathop A\limits^o $