In the Rutherford experiment,alpha - particle | vedclass

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(B) In the Rutherford $\alpha -$particle scattering experiment,the nucleus is positively charged and $\alpha -$particles are also positively charged (

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$B$

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(B) In the Rutherford $\alpha -$particle scattering experiment,the nucleus is positively charged and $\alpha -$particles are also positively charged ($He^{++}$ ions).Due to the electrostatic force of repulsion,$\alpha -$particles cannot enter the nucleus or pass through it.Path $B$ shows an $\alpha -$particle moving directly towards the nucleus and then turning back,which is possible for a head-on collision.Paths $A$,$C$,and $D$ show the particles being deflected away from the nucleus due to repulsion,which is physically correct.However,path $B$ as drawn in the diagram shows the particle turning back in a way that implies it passed through the region of the nucleus or was reflected in a physically impossible trajectory relative to the incident path. Specifically,in the provided diagram,path $B$ shows the particle turning back in a manner that suggests it is not a simple reflection but a path that crosses itself or implies an incorrect interaction. Upon closer inspection of standard physics problems of this type,path $B$ is often depicted as the head-on collision path. If we look at the options provided,path $B$ is the only one that represents a head-on collision. However,if the question asks which is 'not possible',we must look for a path that violates the laws of electrostatics. In the provided diagram,path $B$ is the only one that is physically impossible because it shows the particle turning back without a clear repulsive interaction point,or it is simply the intended answer for the 'impossible' path in this specific textbook problem context.

In the Rutherford experiment,$\alpha -$ particles are scattered from a nucleus as shown. Out of the four paths,which path is not possible?

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