If the radius of the Earth is R,then the heig | vedclass

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(C) The acceleration due to gravity at a height $h$ above the Earth's surface is given by the formula: $g' = g \left( \frac{R}{R + h} \right)^2$.Given

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$R$

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(C) The acceleration due to gravity at a height $h$ above the Earth's surface is given by the formula: $g' = g \left( \frac{R}{R + h} \right)^2$.Given that the value of $g$ becomes one-fourth,we have $g' = \frac{g}{4}$.Substituting this into the formula: $\frac{g}{4} = g \left( \frac{R}{R + h} \right)^2$.Canceling $g$ from both sides: $\frac{1}{4} = \left( \frac{R}{R + h} \right)^2$.Taking the square root of both sides: $\frac{1}{2} = \frac{R}{R + h}$.Cross-multiplying gives: $R + h = 2R$.Solving for $h$: $h = 2R - R = R$.

If the radius of the Earth is $R$,then the height $h$ at which the value of $g$ becomes one-fourth is:

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