If one vertex of an equilateral triangle of side $a$ lies at the origin and another vertex lies on the line $x - \sqrt{3}y = 0$,then the coordinates of the third vertex are:
- A$(0, a)$
- B$(\frac{\sqrt{3}a}{2}, -\frac{a}{2})$
- C$(0, -a)$
- DAll of the above
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