If one root of the quadratic equation ix^2 - | vedclass

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(A) Let the roots of the quadratic equation $ax^2 + bx + c = 0$ be $\alpha$ and $\beta$. Given that one root $\beta = 2 - i$. The product of the roots

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$-i$

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(A) Let the roots of the quadratic equation $ax^2 + bx + c = 0$ be $\alpha$ and $\beta$. Given that one root $\beta = 2 - i$. The product of the roots is given by $\alpha \cdot \beta = \frac{c}{a}$. Here,$a = i$ and $c = 2 - i$. So,$\alpha \cdot (2 - i) = \frac{2 - i}{i}$. Dividing both sides by $(2 - i)$,we get $\alpha = \frac{1}{i}$. Since $\frac{1}{i} = -i$,the other root is $\alpha = -i$.

If one root of the quadratic equation $ix^2 - 2(i + 1)x + (2 - i) = 0$ is $2 - i$,then the other root is

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