Class 11Mathematics4-1.Complex numbers Integral power of iota, Algebraic operations and Equality of complex numbers
Easy$(1 + i)^{10}$,where $i^2 = -1$,is equal to
- A$32i$
- B$64 + i$
- C$24i - 32$
- DNone of these
Explore More
Similar Questions
If $i=\sqrt{-1}$,then $(1+i)^{10}+(1-i)^{10}=$
${\left( \frac{1 + i}{1 - i} \right)^2} + {\left( \frac{1 - i}{1 + i} \right)^2}$ is equal to
Easy
View SolutionWhich of the following statements is true?
Medium
View SolutionThe value of $i^n + i^{n+1} + i^{n+2} + i^{n+3}$ for $n \in N$ is
Medium
View SolutionThe values of $\theta$,for which $\frac{3+2 i \sin \theta}{1-2 i \sin \theta}$ is real are
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo