Express the given complex number in the form | vedclass

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(A) We have $(1-i)^{4} = [(1-i)^{2}]^{2}$.Expanding $(1-i)^{2}$ using the identity $(a-b)^{2} = a^{2} + b^{2} - 2ab$:$(1-i)^{2} = 1^{2} + i^{2} - 2i =

Vedclass · Accepted Answer

$-4$

Vedclass · Answer

(A) We have $(1-i)^{4} = [(1-i)^{2}]^{2}$.Expanding $(1-i)^{2}$ using the identity $(a-b)^{2} = a^{2} + b^{2} - 2ab$:$(1-i)^{2} = 1^{2} + i^{2} - 2i = 1 - 1 - 2i = -2i$.Now,substitute this back into the expression:$(1-i)^{4} = (-2i)^{2}$.Calculate the square:$(-2i)^{2} = (-2)^{2} 	imes i^{2} = 4 	imes (-1) = -4$.Thus,the complex number in the form $a+ib$ is $-4 + 0i$.

Express the given complex number in the form $a+ib$: $(1-i)^{4}$

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