If momentum [ P ], area [ A ] and time [ T ] | vedclass

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Question

Viscosity $=$ pascal.second

$P ^{ x } A ^{ y } T ^{z}=\left[ M ^{1} L ^{-1} T ^{-1}\right]$

$\left[ M ^{1} L ^{+1} T ^{-1}\right]^{ x }\left[ L

Vedclass · Accepted Answer

$\left[ PA ^{-1} T ^{0}\right]$

Vedclass · Answer

Viscosity $=$ pascal.second

$P ^{ x } A ^{ y } T ^{z}=\left[ M ^{1} L ^{-1} T ^{-1}\right]$

$\left[ M ^{1} L ^{+1} T ^{-1}\right]^{ x }\left[ L ^{2}\right]^{y}\left[ T ^{1}\right]^{z}= M ^{1} L ^{-1} T ^{-1}$

$M ^{ x } L ^{+ x +2 y } T ^{- x + z }= M ^{1} L ^{-1} T ^{-1}$

$x=1 \quad x+2 y=-1 \quad-x+z=-1$

$y=-1$

$z=0$

Viscosity $= P ^{1} A ^{-1} T ^{0}$

If momentum $[ P ]$, area $[ A ]$ and time $[ T ]$ are taken as fundamental quantities, then the dimensional formula for coefficient of viscosity is :

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