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Question

$t_{1 / 2} \propto \frac{1}{(	ext { conc. of reactant })^{n-1}}$

For zero order, $n=0$ The half life period $\propto($ conc. of reactant). In the

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$t_{1 / 2} \propto \frac{1}{(	ext { conc. of reactant })^{n-1}}$

For zero order, $n=0$ The half life period $\propto($ conc. of reactant). In the question, the time for half reaction is doubled when initial concentration is doubled it is zero reaction.

If doubling the initial concentration of reactant doubles $t_{1/2}$ of reaction, the order of reaction is

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