The mechanism of the reaction $A + 2B \to D$ is
$2B\xrightarrow{k}{B_2}\,\left[ {Slow} \right]$
${B_2} + A \to D\,\left[ {Fast} \right]$
The rate law expression, order with respect to $A$, order with respect to $'B'$ and overall order of reaction are respectively
$K[B]^2, \,0,\, 2,\, 2$
$K[A]' [B]^2,\, 1,\, 2,\, 3$
$K[A]^2, \,0, \,2,\, 2$
$K[A]^2[B]^1,\, 1, \,2, \,3$
For reaction $2A + B \to $ products, the active mass of $ B $ is kept constant and that of $A$ is doubled. The rate of reaction will then
State a condition under which a bimolecular reaction is kinetically first order reaction.
For the reaction $A + B \rightarrow$ products, it is observed that
$(i)\,\,$on doubling the initial concentration of $A$ only, the rate of reaction is also doubled and
$(ii)$ on doubling the initial concentration of both $A$ and $B,$ there is a change by a factor of $8$ in the rate of the reaction.
The rate of this reaction is given by
Inversion of canesugar in dilute acid (conversion into glucose and fructose) is a
Consider the following reaction,
$2 H _2( g )+2 NO ( g ) \rightarrow N _2( g )+2 H _2 O ( g )$
which following the mechanism given below:
$2 NO ( g ) \underset{ k _{-1}}{\stackrel{ k _1}{\rightleftharpoons}} N _2 O _2( g )$
$N _2 O _2( g )+ H _2( g ) \stackrel{ k _2}{\rightleftharpoons} N _2 O ( g )+ H _2 O ( g )$
$N _2 O ( g )+ H _2( g ) \stackrel{ k _3}{\rightleftharpoons} N _2( g )+ H _2 O ( g )$
(fast equilibrium)
(slow reaction)
(fast reaction)
The order of the reaction is