Medium
For the following reaction: $NO_{2(g)} + CO_{(g)} \to NO_{(g)} + CO_{2(g)}$,the rate law is: $\text{Rate} = k [NO_2]^2$. If $0.1 \ mol$ of gaseous carbon monoxide is added at constant temperature to the reaction mixture,which of the following statements is true?
- ABoth $k$ and the reaction rate remain the same
- BBoth $k$ and the reaction rate increase
- CBoth $k$ and the reaction rate decrease
- DOnly $k$ increases,the reaction rate remains the same
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For the reaction $A + B \rightarrow$ products,doubling the concentration of $A$ increases the reaction rate by four times,but doubling the concentration of $B$ has no effect on the reaction rate. What is the rate law?
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For the reaction $aA + bB \to$ product,the rate of reaction is given by $Rate = k[A]^3 [B]^0$. If the concentration of $A$ is doubled and the concentration of $B$ is halved,the rate of reaction will be: (in $times$)
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View SolutionConsider the gaseous reaction $A_2 + B_2 \rightarrow 2 AB$. The following data was obtained for the above reaction:
$[A_2]_0$ $[B_2]_0$ Initial rate of formation of $AB$ $(mol \ L^{-1} s^{-1})$ $0.1 \ M$ $0.1 \ M$ $2.5 \times 10^{-4}$ $0.2 \ M$ $0.1 \ M$ $5.0 \times 10^{-4}$ $0.2 \ M$ $0.2 \ M$ $1.0 \times 10^{-3}$
The value of the rate constant for the above reaction is:
| $[A_2]_0$ | $[B_2]_0$ | Initial rate of formation of $AB$ $(mol \ L^{-1} s^{-1})$ |
| $0.1 \ M$ | $0.1 \ M$ | $2.5 \times 10^{-4}$ |
| $0.2 \ M$ | $0.1 \ M$ | $5.0 \times 10^{-4}$ |
| $0.2 \ M$ | $0.2 \ M$ | $1.0 \times 10^{-3}$ |
The value of the rate constant for the above reaction is:
DifficultTS EAMCET 2024
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