If initial concentration is reduced to its 1/ | vedclass

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Question

For a zero order reaction, $t _{1 / 2}=\frac{[ A ]_0}{2 k }$

Let $[ A ]_0= a$

$t _{1 / 2}=\frac{ a }{2 k } \ldots \ldots .(1)$

When the intia

Vedclass · Accepted Answer

Becomes one-fourth

Vedclass · Answer

For a zero order reaction, $t _{1 / 2}=\frac{[ A ]_0}{2 k }$

Let $[ A ]_0= a$

$t _{1 / 2}=\frac{ a }{2 k } \ldots \ldots .(1)$

When the intial concentration is reduced to one fourth, $[ A ]_0=\frac{1}{4} 	imes a$.

$t _{1 / 2}^{\prime}=\frac{\frac{1}{4} 	imes a }{2 k } \ldots \ldots .(2)$

By dividing equation $(2)$ by $(1),$ we get

$\frac{t_{1 / 2}^{\prime}}{ t _{1 / 2}}=\frac{\frac{\frac{1}{4} 	imes a }{\frac{ a }{2 k }}}{\frac{1}{4}}=\frac{1}{4}$

Hence, option $C$ is correct.

If initial concentration is reduced to its $1/4^{th}$ in a zero order reaction, the time taken for half of the reaction to complete

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