If it is assumed that the spinning motion of earth increases, then the weight of a body on equator

Assuming earth to be a sphere of a uniform density, what is the value of gravitational acceleration in a mine $100\, km$ below the earth’s surface ........ $m/{s^2}$. (Given $R = 6400 \,km$)

The acceleration due to gravity on a planet is $1.96 \,m / s ^2$. If it is safe to jump from a height of $3 \,m$ on the earth, the corresponding height on the planet will be ........ $m$

The acceleration due to gravity about the earth's surface would be half of its value on the surface of the earth at an altitude of ......... $mile$. ($R = 4000$ mile)

The height ${ }^{\prime} h ^{\prime}$ at which the weight of a body will be the same as that at the same depth $'h'$ from the surface of the earth is (Radius of the earth is $R$ and effect of the rotation of the earth is neglected):

The weight of a body at the surface of earth is $18\,N$. The weight of the body at an altitude of $3200\,km$ above the earth's surface is $........\,N$ (given, radius of earth $R _{ e }=6400\,km$ )