If coefficients of $2^{nd}$,$3^{rd}$ and $4^{th}$ terms in the binomial expansion of $(1 + x)^n$ are in $A.P.$,then $n^2 - 9n$ is equal to

  • A
    $-7$
  • B
    $7$
  • C
    $14$
  • D
    $-14$

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