If both roots of quadratic equation {x^2} + l | vedclass

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Question

$\sin heta+\cos heta<0$ $(\sin heta+\cos heta)^{2}>\frac{3}{2}$ $\sin 2 heta>\frac{1}{2}$ $2 n \pi+\frac{\pi}{6}<2 he

Vedclass · Accepted Answer

$\left( {\frac{{13\pi }}{{12}},\frac{{17\pi }}{{12}}} \right)$

Vedclass · Answer

$\sin heta+\cos heta<0$ $(\sin heta+\cos heta)^{2}>\frac{3}{2}$ $\sin 2 heta>\frac{1}{2}$ $2 n \pi+\frac{\pi}{6}<2 heta<2 n \pi+\frac{5 \pi}{6}$ $n\pi + \frac{\pi }{{12}} < heta < n\pi + \frac{{5\pi }}{{12}}$

If both roots of quadratic equation ${x^2} + \left( {\sin \,\theta + \cos \,\theta } \right)x + \frac{3}{8} = 0$ are positive and distinct then complete set of values of $\theta $ in $\left[ {0,2\pi } \right]$ is

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