If $sin\, \theta = sin\, \alpha$ then $sin\, \frac{\theta }{3}$ =
If $sin\, \theta = sin\, \alpha$ then $sin\, \frac{\theta }{3}$ =
- A
$sin\, \frac{\alpha }{3}$
- B
$sin \, \left( {\frac{\pi }{3} - \frac{\alpha }{3}} \right)$
- C
$- sin \, \left( {\frac{\pi }{3} + \frac{\alpha }{3}} \right)$
- D
All of the above
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