If sin, theta = sin, alpha then sin, frac{the | vedclass

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Question

$sin 	heta = sin \alpha$ 

          $	heta = n\pi +(-1)^n\alpha$

$n = 0$    $	heta = \alpha$  &n

Vedclass · Accepted Answer

All of the above

Vedclass · Answer

$sin 	heta = sin \alpha$ 

          $	heta = n\pi +(-1)^n\alpha$

$n = 0$    $	heta = \alpha$                $sin	heta /3 = sin\alpha /3$

$n = 1$    $	heta = \pi -\alpha$          $sin	heta /3 = sin(\pi /3-\alpha /3)$

$n = -1$    $	heta = -\pi -\alpha$        $sin	heta /3 = sin(-\pi /3-\alpha /3)= -sin(\pi /3+\alpha /3)$

If $sin\, \theta = sin\, \alpha$ then $sin\, \frac{\theta }{3}$ =

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