If $P(B) = \frac{3}{4}$,$P(A \cap B \cap \bar{C}) = \frac{1}{3}$ and $P(\bar{A} \cap B \cap \bar{C}) = \frac{1}{3}$,then $P(B \cap C)$ is

  • A
    $\frac{1}{12}$
  • B
    $\frac{1}{6}$
  • C
    $\frac{1}{15}$
  • D
    $\frac{1}{9}$

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