If f(x) = frac{{{{cos }^2}x + {{sin }^4}x}}{{ | vedclass

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Question

(a) $f(x) = \frac{{{{\cos }^2}x + {{\sin }^4}x}}{{{{\sin }^2}x + {{\cos }^4}x}}$

==> $f(x) = \frac{{{{\cos }^2}x + {{\sin }^2}x(1 - {{\cos }^2}x

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(a) $f(x) = \frac{{{{\cos }^2}x + {{\sin }^4}x}}{{{{\sin }^2}x + {{\cos }^4}x}}$

==> $f(x) = \frac{{{{\cos }^2}x + {{\sin }^2}x(1 - {{\cos }^2}x)}}{{{{\sin }^2}x + {{\cos }^2}x(1 - {{\sin }^2}x)}}$

==> $f(x) = \frac{{{{\sin }^2}x + {{\cos }^2}x - {{\sin }^2}x{{\cos }^2}x}}{{{{\sin }^2}x + {{\cos }^2}x - {{\sin }^2}x{{\cos }^2}x}}$

==> $f(x) = 1$ ==> $f(2002) = 1$.

If $f(x) = \frac{{{{\cos }^2}x + {{\sin }^4}x}}{{{{\sin }^2}x + {{\cos }^4}x}}$ for $x \in R$, then $f(2002) = $

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