If $a > 2b > 0$ then the positive value of m for which $y = mx - b\sqrt {1 + {m^2}} $ is a common tangent to ${x^2} + {y^2} = {b^2}$ and ${(x - a)^2} + {y^2} = {b^2}$, is
$\frac{{2b}}{{\sqrt {{a^2} - 4{b^2}} }}$
$\frac{{\sqrt {{a^2} - 4{b^2}} }}{{2b}}$
$\frac{{2b}}{{a - 2b}}$
$\frac{b}{{a - 2b}}$
If variable point $(x, y)$ satisfies the equation $x^2 + y^2 -8x -6y + 9 = 0$ , then range of $\frac{y}{x}$ is
The equation of circle with centre $(1, 2)$ and tangent $x + y - 5 = 0$ is
The tangent$(s)$ from the point of intersection of the lines $2x -3y + 1$ = $0$ and $3x -2y -1$ = $0$ to circle $x^2 + y^2 + 2x -4y$ = $0$ will be -
The equations of the tangents to the circle ${x^2} + {y^2} = 36$ which are inclined at an angle of ${45^o}$ to the $x$-axis are
The two tangents to a circle from an external point are always