If $x \in R$ and $1 \leq \frac{3x^2-7x+8}{x^2+1} \leq 2$,then the minimum and maximum values of $x$ are respectively.

  • A
    $1, 2$
  • B
    $5, 12$
  • C
    $6, 10$
  • D
    $1, 6$

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