If $\tan \theta = - \frac{1}{{\sqrt 3 }}$ and $\sin \theta = \frac{1}{2}$, $\cos \theta = - \frac{{\sqrt 3 }}{2}$, then the principal value of $\theta $ will be
If $\tan \theta = - \frac{1}{{\sqrt 3 }}$ and $\sin \theta = \frac{1}{2}$, $\cos \theta = - \frac{{\sqrt 3 }}{2}$, then the principal value of $\theta $ will be
- A
$\frac{\pi }{6}$
- B
$\frac{{5\pi }}{6}$
- C
$\frac{{7\pi }}{6}$
- D
$ - \frac{\pi }{6}$
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