If 4{sin ^2}theta + 2(sqrt 3 + 1)cos theta = | vedclass

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Question

(a) $4 - 4{\cos ^2}	heta + 2\,(\sqrt 3 + 1)\cos 	heta = 4 + \sqrt 3 $

$ \Rightarrow $ $4{\cos ^2}	heta - 2\,(\sqrt 3 + 1)\cos 	heta + \sqrt 3 =

Vedclass · Accepted Answer

$2n\pi \pm \frac{\pi }{3}$

Vedclass · Answer

(a) $4 - 4{\cos ^2}	heta + 2\,(\sqrt 3 + 1)\cos 	heta = 4 + \sqrt 3 $

$ \Rightarrow $ $4{\cos ^2}	heta - 2\,(\sqrt 3 + 1)\cos 	heta + \sqrt 3 = 0$

$ \Rightarrow $ $\cos 	heta = \frac{{2(\sqrt 3 + 1) \pm \sqrt {4{{(\sqrt 3 + 1)}^2} - 16\sqrt 3 } }}{8}$

$ \Rightarrow $ $\cos 	heta = \frac{{\sqrt 3 }}{2}{m{ or}}\,\,{m{1/2}}$

$\Rightarrow 	heta = 2n\pi \pm \frac{\pi }{6}$ or $2n\pi \pm \pi /3$.

If $4{\sin ^2}\theta + 2(\sqrt 3 + 1)\cos \theta = 4 + \sqrt 3 $, then the general value of $\theta $ is

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