If ${\tan ^2}\theta - (1 + \sqrt 3 )\tan \theta + \sqrt 3 = 0$, then the general value of $\theta $ is
If ${\tan ^2}\theta - (1 + \sqrt 3 )\tan \theta + \sqrt 3 = 0$, then the general value of $\theta $ is
- A
$n\pi + \frac{\pi }{4},n\pi + \frac{\pi }{3}$
- B
$n\pi - \frac{\pi }{4},n\pi + \frac{\pi }{3}$
- C
$n\pi + \frac{\pi }{4},n\pi - \frac{\pi }{3}$
- D
$n\pi - \frac{\pi }{4},n\pi - \frac{\pi }{3}$
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- [IIT 2015]
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