If sqrt 2 sec theta + tan theta = 1, then the | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) $\sqrt 2 \sec 	heta + 	an 	heta = 1 $

$\Rightarrow \frac{{\sqrt 2 }}{{\cos 	heta }} + \frac{{\sin 	heta }}{{\cos 	heta }} = 1$

$ \Righ

Vedclass · Accepted Answer

$2n\pi - \frac{\pi }{4}$

Vedclass · Answer

(c) $\sqrt 2 \sec 	heta + 	an 	heta = 1 $

$\Rightarrow \frac{{\sqrt 2 }}{{\cos 	heta }} + \frac{{\sin 	heta }}{{\cos 	heta }} = 1$

$ \Rightarrow $ $\sin 	heta - \cos 	heta = - \sqrt 2 $

Dividing by $\sqrt 2 $ on both sides, we get 

$\frac{1}{{\sqrt 2 }}\sin 	heta - \frac{1}{{\sqrt 2 }}\cos 	heta = - 1$

$ \Rightarrow $ $\frac{1}{{\sqrt 2 }}\cos 	heta - \frac{1}{{\sqrt 2 }}\sin 	heta = 1 $

$\Rightarrow \cos \,\left( {	heta + \frac{\pi }{4}} ight) = \cos (0)$

$ \Rightarrow $ $	heta + \frac{\pi }{4} = 2n\pi \pm 0$

$\Rightarrow 	heta = 2n\pi - \frac{\pi }{4}$.

If $\sqrt 2 \sec \theta + \tan \theta = 1,$ then the general value $\theta $ is

Similar Questions

Find the principal and general solutions of the question $\tan x=\sqrt{3}$.

The number of solution of the equation,$\sum\limits_{r = 1}^5 {\cos (r\,x)} $ $= 0$ lying in $(0, \pi)$ is :

If ${\sin ^2}\theta - 2\cos \theta + \frac{1}{4} = 0,$ then the general value of $\theta $ is

Let,$S=\left\{\theta \in[0,2 \pi]: 8^{2 \sin ^{2} \theta}+8^{2 \cos ^{2} \theta}=16\right\}$. Then $n ( S )+\sum_{\theta \in S}\left(\sec \left(\frac{\pi}{4}+2 \theta\right) \operatorname{cosec}\left(\frac{\pi}{4}+2 \theta\right)\right)$ is equal to.

The number of elements in the set $S=$ $\left\{\theta \in[-4 \pi, 4 \pi]: 3 \cos ^{2} 2 \theta+6 \cos 2 \theta-\right.$ $\left.10 \cos ^{2} \theta+5=0\right\}$ is