જો (1 + sin A)(1 + sin B)(1 + sin C) = (1 - s | vedclass

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Question

(b) Multiplying both sides by $(1 - \sin A)(1 - \sin B)(1 - \sin C)$,

we have, $(1 - {\sin ^2}A)(1 - {\sin ^2}B)(1 - {\sin ^2}C)$

$ = {(1 - \sin

Vedclass · Accepted Answer

$ \pm \cos A\cos B\cos C$

Vedclass · Answer

(b) Multiplying both sides by $(1 - \sin A)(1 - \sin B)(1 - \sin C)$,

we have, $(1 - {\sin ^2}A)(1 - {\sin ^2}B)(1 - {\sin ^2}C)$

$ = {(1 - \sin A)^2}{(1 - \sin B)^2}{(1 - \sin C)^2}$

==> $(1 - \sin A)(1 - \sin B)(1 - \sin C) = \pm \cos A\cos B\cos C$

Similarly, $(1 + \sin A)(1 + \sin B)(1 + \sin C) = \pm \cos A\cos B\cos C$.

જો $(1 + \sin A)(1 + \sin B)(1 + \sin C)$$ = (1 - \sin A)(1 - \sin B)(1 - \sin C),$ = . . . . .

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