If sin x + {sin ^2}x = 1, then {cos ^8}x + 2{ | vedclass

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Question

(d) We have $\sin x + {\sin ^2}x = 1\,\,$

$\Rightarrow \,\,\sin x = {\cos ^2}x$

$	herefore$ ${\cos ^8}x + 2{\cos ^6}x + {\cos ^4}x $

$=

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(d) We have $\sin x + {\sin ^2}x = 1\,\,$

$\Rightarrow \,\,\sin x = {\cos ^2}x$

$	herefore$ ${\cos ^8}x + 2{\cos ^6}x + {\cos ^4}x $

$= {\sin ^4}x + 2{\sin ^3}x + {\sin ^2}x$

$ = {(\sin x + {\sin ^2}x)^2} = 1$.

If $\sin x + {\sin ^2}x = 1,$ then ${\cos ^8}x + 2{\cos ^6}x + {\cos ^4}x = $

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