If sin theta = - frac{1}{{sqrt 2 }} and tan t | vedclass

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Question

(c) $\sin 	heta = - \frac{1}{{\sqrt 2 }}$ and $	an 	heta = 1$

$ \Rightarrow $$\sin 	heta = \sin 225^\circ \Rightarrow 	heta = 225^\circ $

S

Vedclass · Accepted Answer

Third

Vedclass · Answer

(c) $\sin 	heta = - \frac{1}{{\sqrt 2 }}$ and $	an 	heta = 1$

$ \Rightarrow $$\sin 	heta = \sin 225^\circ \Rightarrow 	heta = 225^\circ $

Since $\sin 	heta $ is $ - ve$ and $	an 	heta $is $ + ve$ in third quadrant.

If $\sin \theta = - \frac{1}{{\sqrt 2 }}$ and $\tan \theta = 1,$ then $\theta $ lies in which quadrant

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