यदि $p{\lambda ^4} + q{\lambda ^3} + r{\lambda ^2} + s\lambda + t = \left| {\begin{array}{*{20}{c}}{{\lambda ^2} + 3\lambda }&{\lambda - 1}&{\lambda + 3}\\{\lambda + 1}&{2 - \lambda }&{\lambda - 4}\\{\lambda - 3}&{\lambda + 4}&{3\lambda }\end{array}} \right|$ है,तो $t$ का मान ज्ञात कीजिए।

  • A
    $16$
  • B
    $18$
  • C
    $17$
  • D
    $19$

Explore More

Similar Questions

दिए गए समीकरण $\left| \begin{array}{ccc} x+a & b & c \\ b & x+c & a \\ c & a & x+b \end{array} \right| = 0$ का एक मूल क्या है?

यदि $A = \begin{bmatrix} \alpha & 2 \\ 2 & \alpha \end{bmatrix}$ और $|A^3| = 27$ है,तो $\alpha = $

यदि $\Delta=\left|\begin{array}{lll}1 & a & a^2 \\ 1 & b & b^2 \\ 1 & c & c^2\end{array}\right|=K(a-b)(b-c)(c-a)$,तो $K=$

मान लीजिए $x, y, z > 0$ क्रमशः $G.P.$ के $2^{nd}, 3^{rd}, 4^{th}$ पद हैं,और $\Delta = \begin{vmatrix} x^k & x^{k+1} & x^{k+2} \\ y^k & y^{k+1} & y^{k+2} \\ z^k & z^{k+1} & z^{k+2} \end{vmatrix} = (r-1)^2 \left(1 - \frac{1}{r^2}\right)$,जहाँ $r$ सार्व अनुपात है। तो $k = \dots$

आव्यूह $\left[ {\begin{array}{*{20}{c}}2&\lambda &{ - 4}\\{ - 1}&3&4\\1&{ - 2}&{ - 3}\end{array}} \right]$ व्युत्क्रमणीय (non-singular) है,यदि

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo