If x,;y,;z are in G.P. and {a^x} = {b^y} = {c | vedclass

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(b) $x,\;y,\;z$ are in $G.P.$, then ${y^2} = x\;.\;z$

Now ${a^x} = {b^y} = {c^z} = m$

$ \Rightarrow $ $x{\log _e}a = y{\log _e}b = z{\log _e}c =

Vedclass · Accepted Answer

${\log _b}a = {\log _c}b$

Vedclass · Answer

(b) $x,\;y,\;z$ are in $G.P.$, then ${y^2} = x\;.\;z$

Now ${a^x} = {b^y} = {c^z} = m$

$ \Rightarrow $ $x{\log _e}a = y{\log _e}b = z{\log _e}c = {\log _e}m$

$ \Rightarrow $ $x = {\log _a}m,\;y = {\log _b}m,z = {\log _c}m$

Again as $x,\;y,\;z$ are in $G.P.$,

so $\frac{{y}}{x}=\frac{{z}}{y}$

$ \Rightarrow $$\frac{{{{\log }_b}m}}{{{{\log }_a}m}} = \frac{{{{\log }_c}m}}{{{{\log }_b}m}}$

$ \Rightarrow $${\log _b}a = {\log _c}b$.

If $x,\;y,\;z$ are in $G.P.$ and ${a^x} = {b^y} = {c^z}$, then

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