If ${\log _7}2 = m,$ then ${\log _{49}}28$ is equal to
If ${\log _7}2 = m,$ then ${\log _{49}}28$ is equal to
- A
$2\,(1 + 2m)$
- B
${{1 + 2m} \over 2}$
- C
${2 \over {1 + 2m}}$
- D
$1 + m$
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