If ${\log _7}2 = m,$ then ${\log _{49}}28$ is equal to
$2\,(1 + 2m)$
${{1 + 2m} \over 2}$
${2 \over {1 + 2m}}$
$1 + m$
If ${x^{{3 \over 4}{{({{\log }_3}x)}^2} + {{\log }_3}x - {5 \over 4}}} = \sqrt 3 $ then $x$ has
For $y = {\log _a}x$ to be defined $'a'$ must be
The set of real values of $x$ satisfying ${\log _{1/2}}({x^2} - 6x + 12) \ge - 2$ is
The value of $6+\log _{\frac{3}{2}}\left(\frac{1}{3 \sqrt{2}} \sqrt{4-\frac{1}{3 \sqrt{2}} \sqrt{4-\frac{1}{3 \sqrt{2}} \sqrt{4-\frac{1}{3 \sqrt{2}} \ldots}}}\right)$ is
Solution set of inequality ${\log _{10}}({x^2} - 2x - 2) \le 0$ is