If $\oint_s \vec{E} \cdot \overrightarrow{d S}=0$ over a surface, then:

  • [NEET 2023]
  • A

    the electric field inside the surface is necessarily uniform.

  • B

    the number of flux lines entering the surface must be equal to the number of flux lines leaving it.

  • C

    the magnitude of electric field on the surface is constant.

  • D

    all the charges must necessarily be inside the surface.

Similar Questions

When electric flux is said to be positive, negative or zero ?

$(a)$ An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?

$(b)$ Explain why two field lines never cross each other at any point?

Figure shows four charges $q_1, q_2, q_3$ and $q_4$ fixed in space. Then the total flux of electric field through a closed surface $S$, due to all charges $q_1, q_2, q_3$ and $q_4$ is

A charged particle $q$ is placed at the centre $O$ of cube of length $L$ $(A\,B\,C\,D\,E\,F\,G\,H)$. Another same charge $q$ is placed at a distance $L$ from $O$.Then the electric flux through $BGFC$ is

  • [AIEEE 2002]

Let the electrostatic field $E$ at distance $r$ from a point charge $q$ not be an inverse square but instead an inverse cubic, e.g. $E =k \cdot \frac{q}{r^{3}} \hat{ r }$, here $k$ is a constant.

Consider the following two statements:

$(I)$ Flux through a spherical surface enclosing the charge is $\phi=q_{\text {enclosed }} / \varepsilon_{0}$.

$(II)$ A charge placed inside uniformly charged shell will experience a force.

Which of the above statements are valid?

  • [KVPY 2017]