If oint_s vec{E} cdot overrightarrow{d S}=0 o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given expression $\oint_s \vec{E} \cdot \overrightarrow{d S} = 0$ represents the total electric flux $\phi$ through a closed surface.According

Vedclass · Accepted Answer

the number of flux lines entering the surface must be equal to the number of flux lines leaving it.

Vedclass · Answer

(B) The given expression $\oint_s \vec{E} \cdot \overrightarrow{d S} = 0$ represents the total electric flux $\phi$ through a closed surface.According to Gauss's Law,the total flux through a closed surface is equal to the net charge enclosed divided by the permittivity of free space,$\phi = \frac{q_{	ext{enclosed}}}{\epsilon_0}$.Since the total flux is zero,the net charge enclosed by the surface must be zero $(q_{	ext{enclosed}} = 0)$.This implies that the number of electric field lines entering the surface is exactly equal to the number of electric field lines leaving the surface,resulting in a net flux of zero.

If $\oint_s \vec{E} \cdot \overrightarrow{d S}=0$ over a surface,then:

Similar Questions

$A$ point charge of $+12 \,\mu C$ is at a distance $6 \,cm$ vertically above the centre of a square of side $12 \,cm$ as shown in the figure. The magnitude of the electric flux through the square will be ....... $\times 10^{3} \,Nm^{2}/C$.

$A$ large number of positive charges,each of magnitude $q$,are placed along the $X$-axis at the origin and at every $1 \text{ cm}$ distance in both directions. The electric flux through a spherical surface of radius $2.5 \text{ cm}$ centered at the origin is

There exists an electric field of $1 \ N/C$ along the $Y$-direction. The flux passing through a square of $1 \ m^2$ placed in the $XY$-plane inside the electric field is . . . . . . .

Give a reason: 'If the net flux associated with a closed surface is zero,then the net charge enclosed by that surface is zero.'

$A$ Gaussian surface of radius $R$ encloses a charge $Q$. If the radius is doubled,the outward electric flux will...

Vedclass Test Series

Exam Paper Generator

Online Exam Module